Cathode bias review
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Cathode bias review
I forgot why aned would appreciate a quick reviewof the following. Why does a 6v6 cathode biased amp use a 250 0hm resistor if both cathodes are biased but a 500 ohm resistor if they are wired independent of each other?
- David Root
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Re: Cathode bias review
Because two 500 ohm resistors in parallel equals 250 ohms.
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vibratoking
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Re: Cathode bias review
So, I'm gonna jump in and teach you to fish instead of giving you a fish. This is BASIC stuff and is not something that you should forget because you should be able to figure it out with only basic knowledge.sdorer wrote:I forgot why aned would appreciate a quick reviewof the following. Why does a 6v6 cathode biased amp use a 250 0hm resistor if both cathodes are biased but a 500 ohm resistor if they are wired independent of each other?
Look at method 2 in this link:
http://www.wikihow.com/Calculate-Series ... Resistance
You should know this, and all the other methods on that page, if you plan on playing with any kind of electronics.
Now think about what the voltage is on the top side of those parallel resistors using V=IR. In your example, you want the cathode(s), or top side, voltage to be the same in order to achieve the same bias conditions assuming matched tubes. How are you gonna do that?
Electronic equipment is designed using facts and mathematics, not opinion and dogma.
Re: Cathode bias review
And along the lines of what vibratoking said:
V = I x R
where:
V = Voltage (in Volts)
I = Current (in Amps)
R = Resistance (in Ohms)
Some worked examples:
1 Volt = 1 Amp x 1 Ohm
2 Volts = 2 Amps x 1 Ohm (or = 1 Amp x 2 Ohms)
20 Volts = 20 Amps x 1 Ohm (or = 1 Amp x 20 Ohms, or = 0.1A x 200 Ohms, or = 0.08 Amps* x 250 Ohms, or = 0.04A** x 500 Ohms) etc
*80mA which is about the total tube current of two 6V6s combined
**40mA which is about the tube current through one 6V6
V = I x R
where:
V = Voltage (in Volts)
I = Current (in Amps)
R = Resistance (in Ohms)
Some worked examples:
1 Volt = 1 Amp x 1 Ohm
2 Volts = 2 Amps x 1 Ohm (or = 1 Amp x 2 Ohms)
20 Volts = 20 Amps x 1 Ohm (or = 1 Amp x 20 Ohms, or = 0.1A x 200 Ohms, or = 0.08 Amps* x 250 Ohms, or = 0.04A** x 500 Ohms) etc
*80mA which is about the total tube current of two 6V6s combined
**40mA which is about the tube current through one 6V6
He who dies with the most tubes... wins
Re: Cathode bias review
Question: Okay, fine and dandy with all the formulas and stuff. How does that make the big resistor like a small resistor?
Answer: Valentine's Day.
Answer: Valentine's Day.
What?
- johnnyreece
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Re: Cathode bias review
Ba-dum CHHHH!Structo wrote:These threads are always so biased.
Re: Cathode bias review
Ha, exactly.johnnyreece wrote:Ba-dum CHHHH!Structo wrote:These threads are always so biased.
And these threads always seem to degenerate into feedback, sometimes smooth, but sometimes harsh if the debate is grossly imbalanced and there's unpleasant effects from distortion of the truth.
Re: Cathode bias review
It is to keep the bias voltage the same. The bias voltage is developed by current flowing through the cathode resistor. So suppose each tube is drawing a current I. And suppose they share a single cathode resistor R. So, then the voltage of the cathodes will be elevated by:sdorer wrote:I forgot why aned would appreciate a quick reviewof the following. Why does a 6v6 cathode biased amp use a 250 0hm resistor if both cathodes are biased but a 500 ohm resistor if they are wired independent of each other?
V = (2 * I) * R
Now if you use an independent resistor for each tube the current (for a single tube) will still be the same. And if you keep the resistance the same your bias voltage will drop by half (Vbias_to_low = I * R). So, you double the value of R to keep the bias voltage the same.
Mike
Re: Cathode bias review
Vir bonus dicendi peritus