You need some capacitance to charge up and hold the DC at the peak level of the AC voltage, otherwise you are just measuring a rectified version of the AC waveform, which is the AC rms voltage times 1.000.sliberty wrote:I haven't worked on this amp in a few days, but I put it back on teh bench last night, pulled all tubes, and measured the DC just after the diodes - 370V. Should have been closer to 420V.LeftyStrat wrote:Actually that sounds about right to me. The 1.414 figure is for unloaded. Under load 1.2 is usually ballpark. So 293*1.2 = 352.
Tried new diodes with no improvement.
If I disconnect the diodes from the rest of the amp (filters and beyond), and measure again at the diodes, what should I expect? Is it valid to measure with nothing connected like that?
Measure your AC voltage and your rectified and filtered DC voltages under the same condition whether loaded or unloaded and subtract the drop across the rectifier. It's as simple as that, there's no where else for the voltage to go unless there's some other unidentified problem dropping the voltage.
Either way you should be able to identify where the voltage is being lost by careful measurements.
You can also measure the ripple on the capacitor to verify that it's actually holding a charge, which it may not be.
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