My Wreck wa built in a donor chassis from a 70's Univox PA head. It had 8 inputs in the area where I wanted to put my 1 input. But there wasn't enough metal to drill a centrally positioned mounting hole. So I decided to use two inputs and make use of some existing holes.
Currently, I only have 1 input wired in, according to the Kelly schematic and layout. I'd like to now wire up the second jack, in a way that will make it a "low" input compared to the normal "hi" input. Perhaps the way to go is with the 1meg / 68K arrangement [opinions requested here]. But even if so, do I simply attach it to the V1 pin 7, in parallel to the normal input? I am hoping not to impact the normal tone in the normal jack.
Any thoughts would be appreciated. A diagram would be really helpful too, since I am sometimes a little slow catching on
No, the thing is, that they all use the 68K / 1M resistor layout. I don't want to effect the touch sensative nature of the wreck, so I don't want to insert a 68k on the "normal channel. But I do want a low channel. So can I have one with and one without the 68k resistor?
hey steve, your best bet is to just use the extra jack hole (if you've drilled one) for a 1m mini pot in series with a 68k resistor to replace the 1m load resistor across your input jack. this way you could vary the load resistance however much you wanted all the way down to 68k (or lower if you used a lower resistor) and not have any input series resistor to the input tube like you wanted. all the way up the load is 1m + 68k which effectively is the same as 1m. rh
rh - Your idea worked out really well. I put a mini 1meg pot in the extra hole (it just barely cleared the font panel for the nut), and hooked it to the jack in place of the 1meg resistor. I may still play with the pot value a little bit before I am done (my pot measured only 881k), but the result was just what I was just exactly looking for, only better because now I don't have to unplug/replug to get the benefit of the lower level input.
BTW - I didn't use a 68k resistor to limit the input loss. If I turn the control fully counter clockwise, the input is totally shunted to ground, and there is no sound. I am OK with this, but I wondered if this is a bad idea for any reason. Your thoughts?
